🧪 Contents · Interactive Lab Chapter 18 · Representative Metals, Metalloids and Nonmetals
Chemistry · Chapter 18

Representative Metals, Metalloids and Nonmetals

The main groups are the two tall columns on the left of the periodic table and the six on the right. They hold the elements you meet every day. Table salt, lime, sand, glass, rust proofing, fertilizer, bleach and battery acid all come from them. This chapter walks group by group through those elements. You will see why sodium explodes in water while magnesium barely fizzes. You will see why carbon can be the hardest solid or the slipperiest one. And you will see why the noble gases sit out almost every reaction. The rules behind all of it come from two trends you already know.

By the end of this chapter you can

  • Explain how metallic character shifts across a row and down a group, and link it to size and ionization energy.
  • Sort main group oxides as basic, acidic or amphoteric, and write the water reaction for each kind.
  • Write balanced equations for group 1 and group 2 metals reacting with water, oxygen and nitrogen.
  • Compare the allotropes of carbon and the silicate structures, and tie each one to a real use.
  • Trace nitrogen through the Haber and Ostwald processes, and rank the phosphorus acids by how many protons they give up.
  • Describe the contact process for sulfuric acid, and tell oxides, peroxides and superoxides apart.
  • Rank the halogens by oxidizing strength, predict a displacement reaction, and name the xenon fluorides.

Section 1Periodicity of the main groups

One outer shell, one personality

The main group elements fill groups 1, 2 and 13 through 18. They are also called the representative elements. What ties a group together is its outer shell. Every group 1 atom has one electron in its outer s orbital. Every group 17 atom has seven outer electrons. That count is the valence electron count. It sets the charges an element forms. It also sets how many bonds the atom makes.

Two trends explain most of this chapter. The first is size. The second is how tightly the nucleus grips the outer electrons. Chemists measure that grip with effective nuclear charge, written Zeff. It is the charge an outer electron really feels. Inner electrons screen part of the true nuclear charge.

Metallic character across and down the main groups 1 2 13 14 15 16 17 18 2 Li Be B C N O F Ne 3 Na Mg Al Si P S Cl Ar 4 K Ca Ga Ge As Se Br Kr 5 Rb Sr In Sn Sb Te I Xe Group Period across a period: more nonmetal, oxides turn acidic down a group: more metallic metal metalloid nonmetal noble gas
The main group map. Metals (teal) crowd the left and the bottom. Nonmetals (grey) crowd the top right. The metalloids (gold) run as a staircase between them. Read across for rising nonmetal character and down for rising metallic character.

Across a period the grip tightens

Walk from sodium to chlorine. Each step adds one proton and one outer electron. The new electron joins a shell that is already there, so it screens badly. Zeff climbs at every step. Atoms shrink and hold their electrons harder. Ionization energy rises from 496 kJ/mol for sodium to 1251 kJ/mol for chlorine. Electronegativity rises as well, from 0.93 to 3.16.

So the left side hands electrons out and the right side takes them in. That shift is a loss of metallic character. Sodium is a soft shiny metal. Silicon is a metalloid, shiny but a weak conductor. Chlorine is a gas that grabs electrons from almost anything.

Worked example · a quick Zeff estimate

Compare the pull on an outer electron in sodium and in chlorine. Treat the filled inner shells as perfect screens.

Step 1 · count the coreSodium has 11 protons. Ten of its electrons sit in filled inner shells.

Step 2 · subtractZeff ≈ 11 − 10 = +1.

Step 3 · repeat for chlorineChlorine has 17 protons and the same 10 core electrons. Zeff ≈ 17 − 10 = +7.

Step 4 · read the answerThe outer electron in chlorine feels about seven times the pull. That is why chlorine is far smaller than sodium. It is also why it takes 1251 kJ/mol to strip an electron from chlorine and only 496 kJ/mol from sodium. Real screening is not perfect, so these numbers are a ceiling, not an exact value.

Down a group the grip loosens

Now move from lithium to cesium. Each step adds a whole new shell. The outer electron sits farther out, and more core electrons screen it. The atomic radius grows from 152 pm to 265 pm. Ionization energy drops from 520 kJ/mol to 376 kJ/mol. A looser grip means the atom gives an electron up more easily. So metallic character grows down every main group.

Group 14 shows this best. Carbon at the top is a nonmetal. Silicon and germanium are metalloids. Tin and lead at the bottom are metals soft enough to hammer flat. One group, three kinds of element, and the only change is shell count.

Oxides give the game away

You can place an element by how its oxide treats water. A basic oxide comes from a metal and makes a base:

Na2O(s) + H2O(l) → 2 NaOH(aq)

An acidic oxide comes from a nonmetal and makes an acid:

SO3(g) + H2O(l) → H2SO4(aq)

Between them sits the amphoteric oxide, which reacts with acid and with base. Aluminum oxide is the textbook case. It dissolves in strong acid and in strong base, and it shrugs off water:

Al2O3(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2O(l) Al2O3(s) + 2 NaOH(aq) + 3 H2O(l) → 2 Na[Al(OH)4](aq)
Period 3 oxideNa2OMgOAl2O3SiO2P4O10SO3Cl2O7
Acid or basestrong basebaseamphotericweak acidacidstrong acidstrongest acid
Bondingionicionicionic, part covalentcovalent networkmolecularmolecularmolecular
Melting point (°C)113228522072171334017−92
Worth knowing. Ionization energy does not rise in a perfect line. Aluminum (578 kJ/mol) sits below magnesium (738 kJ/mol), and sulfur (1000 kJ/mol) sits below phosphorus (1012 kJ/mol). Each dip marks the start of a new orbital or a new electron pairing. The big picture still holds.
Key points
  • Main group means groups 1, 2 and 13 through 18. Outer s and p electrons run the show.
  • Across a period, Zeff rises, atoms shrink, and ionization energy and electronegativity rise.
  • Down a group, a new shell is added. Atoms grow, ionization energy falls, metallic character rises.
  • Oxides shift from basic to amphoteric to acidic as you move left to right.
  • Aluminum oxide is amphoteric. That one fact places aluminum right on the metal border.
Interactive Move across and down the main groups and track the pattern. Open full ↑

Section 2Alkali and alkaline earth metals

Group 1: one electron to lose

The alkali metals are lithium, sodium, potassium, rubidium, cesium and francium. Each one has a single outer s electron. Each one loses it to make a +1 ion. None of them is ever found free in nature. All are soft enough to cut with a knife, and all are stored under oil. Air and water attack them on contact.

In water they all do the same thing. They make hydrogen gas and a hydroxide:

2 Na(s) + 2 H2O(l) → 2 NaOH(aq) + H2(g)

The equation is the same for every member. The speed is not. Lithium fizzes steadily. Sodium melts into a ball and darts across the surface. Potassium lights its own hydrogen with a lilac flame. Cesium reacts so fast it can crack the glass. Ionization energy explains the ladder. It takes 520 kJ/mol to strip lithium and only 376 kJ/mol to strip cesium.

First ionization energy falls down group 1 and group 2 First ionization energy (kJ/mol) and what the metal does in water 0 200 400 600 800 Li Be 520 · fizzes steadily 899 · no reaction Na Mg 496 · melts, darts about 738 · needs steam K Ca 419 · lilac flame 590 · steady fizz Rb Sr 403 · violent 549 · brisk Cs Ba 376 · explosive 503 · fast reactivity with water rises group 1 (alkali) group 2 (alkaline earth)
Down both groups the first electron gets cheaper. Group 1 (teal) always costs less than the group 2 metal beside it (gold). Water reactions track those numbers, with one famous exception noted below.

Oxygen gives three different products, and which one you get depends on the metal. Lithium makes a plain oxide. Sodium makes a peroxide, with an O–O bond. Potassium and the heavier metals make a superoxide:

4 Li(s) + O2(g) → 2 Li2O(s) 2 Na(s) + O2(g) → Na2O2(s) K(s) + O2(g) → KO2(s)

Lithium has one more trick. It is the only group 1 metal that attacks nitrogen gas at room temperature:

6 Li(s) + N2(g) → 2 Li3N(s)

Sodium metal itself is made by electrolysis. Molten sodium chloride runs in a Downs cell at about 600 °C. Calcium chloride is mixed in to drop the melting point. Sodium forms at the cathode and chlorine at the anode:

Na+ + e− → Na(l)     2 Cl− → Cl2(g) + 2 e−
Worth knowing. Lithium has the most negative standard reduction potential of the lot, −3.04 V. On paper it should be the most eager to react. In water it is the slowest. Its high melting point keeps it solid, and its hydroxide coats the surface. Speed and driving force are two different things.

Group 2: two electrons, a tighter hold

The alkaline earth metals are beryllium, magnesium, calcium, strontium, barium and radium. Each has two outer s electrons and forms a +2 ion. Pulling two electrons off costs much more than pulling one off. So group 2 metals are harder, denser and far less reactive than their group 1 neighbours.

Water shows the gap clearly. Beryllium does not react at all, even in steam. Magnesium needs steam to get going. Calcium works away in cold water at a steady pace:

Mg(s) + H2O(g) → MgO(s) + H2(g) Ca(s) + 2 H2O(l) → Ca(OH)2(aq) + H2(g)

Magnesium burns in air with a white glare hot enough to melt steel. That is why it once filled flash bulbs and still fills emergency flares:

2 Mg(s) + O2(g) → 2 MgO(s)

The lime cycle

Limestone is calcium carbonate. Heat it past about 900 °C in a kiln and it gives up carbon dioxide. The product is quicklime, calcium oxide:

CaCO3(s) → CaO(s) + CO2(g)    ΔH = +179.2 kJ

Add water to quicklime and it hisses, swells and gets hot. That gives slaked lime, calcium hydroxide:

CaO(s) + H2O(l) → Ca(OH)2(s)    ΔH = −65 kJ

Lime mortar then closes the loop. Over months it pulls carbon dioxide back out of the air and turns to stone again. Farmers spread lime on sour soil, and power plants use it to trap sulfur dioxide from flue gas. Hard water is the same chemistry working against you. Dissolved Ca2+ and Mg2+ ions leave scale in kettles and pipes.

Worked example · hydrogen from sodium and water

Drop 2.30 g of sodium into excess water. How much hydrogen gas forms at 0 °C and 1.00 atm? How much sodium hydroxide do you end up with?

Step 1 · moles of sodium2.30 g ÷ 22.99 g/mol = 0.1000 mol Na.

Step 2 · use the ratioThe equation gives 1 mol H2 for every 2 mol Na. So 0.1000 mol ÷ 2 = 0.0500 mol H2.

Step 3 · find the volumeV = nRT/P = (0.0500 mol)(0.08206 L·atm/mol·K)(273.15 K) ÷ 1.00 atm = 1.12 L.

Step 4 · find the baseSodium and hydroxide come out 1 to 1. So 0.1000 mol NaOH × 40.00 g/mol = 4.00 g NaOH. Check it a second way. 2.30 g Na plus the oxygen and hydrogen it picks up has to weigh more, and 4.00 g does.

PropertyGroup 1Group 2
Outer electronsns1ns2
Ion formedM+M2+
First ionization energy376–520 kJ/mol503–899 kJ/mol
Cold waterall react, fast to violentBe no, Mg slow, Ca–Ba yes
Hydroxide solubilityall very solublerises down the group
Flame colourLi crimson, Na yellow, K lilacCa orange, Sr red, Ba green
Oxide in waterstrong basebase, BeO amphoteric
Key points
  • Group 1 metals lose one electron, group 2 metals lose two. Both get easier to strip down the group.
  • Every alkali metal gives hydrogen plus a hydroxide in water. Only the speed changes.
  • Lithium alone makes a nitride with N2 at room temperature. Sodium favours the peroxide with oxygen, potassium the superoxide.
  • Beryllium oxide and hydroxide are amphoteric. The rest of group 2 gives plain bases.
  • The lime cycle runs limestone → quicklime → slaked lime → limestone, and it drives mortar, soil treatment and flue gas scrubbing.
Interactive Drop group 1 and 2 metals in water and compare the reaction. Open full ↑

Section 3Boron, aluminum, carbon and silicon

Boron is short of electrons

Boron is the only member of group 13 that is not a metal. It is a hard, dark metalloid that melts near 2075 °C. It has three valence electrons, which is one short of a filled set of four bonds. That shortage runs all of its chemistry. Boron compounds hunt for electron pairs, so they act as Lewis acids. Boron trifluoride, BF3, grabs a pair from almost any donor.

Diborane, B2H6, shows the shortage best. It has 12 valence electrons but needs 16 for eight normal bonds. Two hydrogens solve this by bridging. Each bridge is a three-center two-electron bond, with one pair shared across B–H–B. Boron is electron deficient, not broken.

Boric acid, H3BO3, is a mild antiseptic and a very weak acid. It does not hand over its own proton. It takes a hydroxide from water instead, which leaves an H+ behind:

B(OH)3(aq) + 2 H2O(l) ⇌ B(OH)4−(aq) + H3O+(aq)    Ka = 5.8 × 10−10

Borax, Na2B4O7·10H2O, is the mined ore. Boron oxide, B2O3, goes into borosilicate glass, which barely expands when heated.

Aluminum is common, armoured and two-faced

Aluminum is the most plentiful metal in the crust, near 8% by mass. It is never free, because it holds oxygen too tightly. Pulling it out needs electricity. In the Hall–Héroult process, alumina is dissolved in molten cryolite, Na3AlF6, near 960 °C. Carbon anodes burn away as the oxide gives up its oxygen:

2 Al2O3(l) + 3 C(s) → 4 Al(l) + 3 CO2(g)

Fresh aluminum looks like it should corrode away. It does not, because the surface grows a thin tight film of Al2O3 that seals the metal below. Anodizing thickens that film on purpose. Aluminum is also an amphoteric metal. It dissolves in strong acid and in strong base, giving hydrogen both times:

2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g) 2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 Na[Al(OH)4](aq) + 3 H2(g)

Aluminum wants oxygen so badly that it will steal it from other metal oxides. The thermite reaction uses that hunger to weld rail track in the field:

2 Al(s) + Fe2O3(s) → Al2O3(s) + 2 Fe(l)    ΔH = −852 kJ

Worked example · how much aluminum a current makes

A smelting cell passes 1.00 × 106 C of charge. What mass of aluminum forms? Use F = 96,485 C/mol.

Step 1 · moles of electrons1.00 × 106 C ÷ 96,485 C/mol = 10.36 mol e−.

Step 2 · the half reactionAl3+ + 3 e− → Al. Each atom costs three electrons.

Step 3 · moles of metal10.36 mol ÷ 3 = 3.455 mol Al.

Step 4 · mass3.455 mol × 26.98 g/mol = 93.2 g. That is why a smelter is built next to a power station.

Carbon: one atom, many solids

Carbon forms more allotropes than any other element. An allotrope is a different solid form of the same element. In diamond every carbon bonds to four others at 109.5°, with bonds 154 pm long. The whole crystal is one giant molecule. Nothing can slide and no electron is free, so diamond is the hardest natural solid and a poor conductor.

In graphite each carbon bonds to only three others in a flat sheet. Those bonds are 142 pm long and very strong. The fourth electron sits in a p orbital above and below the sheet, and it roams. Sheets lie 335 pm apart and are held by weak forces only. So graphite conducts along its sheets and slides apart in your pencil.

Diamond and graphite: same atoms, different bonding Two carbons: a rigid 3D network and a stack of flat sheets Diamond · sp³, 109.5° 154 pm Every carbon holds four neighbours. No loose electrons, so it does not conduct. Hardest natural solid. Melts near 3550 °C. Used in drill bits and heat spreaders. Graphite · sp², flat sheets 335 pm apart 142 pm in sheet Three strong bonds per atom, one spare p electron. Those spare electrons roam, so graphite conducts. Weak forces between sheets let them slide.
Hard versus slippery. Diamond locks every carbon into a rigid three dimensional net. Graphite spends three bonds in the sheet and leaves one electron loose. The gap between the sheets is more than twice the bond length inside one.

Two newer allotropes matter too. A single graphite sheet on its own is graphene. Roll it up and you get a nanotube. Buckminsterfullerene, C60, is a hollow ball of 20 hexagons and 12 pentagons.

Silicon builds the ground you stand on

Silicon is second only to oxygen in the crust, near 28% by mass. You never find it free. Every silicon atom in rock is tied to oxygen in a silicate. The unit is a tetrahedron, one silicon in the middle with four oxygens at the corners. Those tetrahedra share corners, and how many they share decides the mineral.

Carbon and silicon sit in the same group, so why is CO2 a gas and SiO2 a rock? Carbon is small, so its p orbitals overlap sideways well and give strong double bonds. One carbon with two double bonds is a complete molecule. Silicon is bigger and that sideways overlap is poor. So silicon makes four single bonds to oxygen instead, and the solid never ends.

Silicate structures from single tetrahedra to a full network One building block, four different minerals Single tetrahedron SiO44− corners shared: 0 olivine, zircon separate ions Chain (SiO32−)n corners shared: 2 pyroxene, asbestos fibres Sheet (Si2O52−)n corners shared: 3 mica, clay, talc flakes Full network SiO2 corners shared: 4 quartz, sand, glass hard 3D solid
Sharing corners. Share none and you get separate SiO44− ions, as in olivine. Share two and you get chains, which is why asbestos comes as fibres. Share three and you get sheets, so mica peels. Share all four and you get quartz.

Pure silicon starts as sand reduced with coke in an arc furnace. Chip grade silicon needs a second pass through a liquid:

SiO2(s) + 2 C(s) → Si(l) + 2 CO(g) Si(s) + 3 HCl(g) → SiHCl3(g) + H2(g)

The trichlorosilane is distilled, then broken back down to deposit pure silicon. Chips need fewer than one stray atom per billion.

Worth knowing. Structure beats composition. Asbestos and talc are both magnesium silicates. Asbestos is built from chains, so it splits into sharp needles that lodge in the lung. Talc is built from sheets, so it flakes into soft powder. Same elements, very different risk.
Key points
  • Boron is electron deficient. Its compounds act as Lewis acids, and diborane bridges with three-center two-electron bonds.
  • Boric acid takes OH− from water instead of donating its own proton.
  • Aluminum is won by electrolysis in molten cryolite. Its oxide film protects it, and the metal is amphoteric.
  • Diamond is a four bond network and an insulator. Graphite is a three bond sheet with a loose electron, so it conducts and lubricates.
  • Silicates are SiO4 tetrahedra sharing corners. More sharing means a tougher, less soluble mineral.
  • CO2 is a gas and SiO2 is a solid because strong double bonds need small atoms.
Interactive Compare the structures and uses of group 13 and 14 elements. Open full ↑

Section 4Nitrogen and phosphorus

Nitrogen is locked in a triple bond

Nitrogen gas is 78% of the air you breathe, yet almost nothing reacts with it. The reason is one number. The N≡N triple bond is worth 945 kJ/mol and is only 110 pm long. It is one of the strongest bonds known. Breaking it is the whole problem of nitrogen fixation, which means turning N2 into a form life can use.

Industry solves it with the Haber process. Nitrogen from air meets hydrogen from steam reforming over an iron catalyst:

N2(g) + 3 H2(g) ⇌ 2 NH3(g)    ΔH = −92.2 kJ

The forward reaction gives out heat and shrinks the gas volume. So cold and squeezed should give the best yield. But cold is also slow. Real plants run near 450 °C and 200 atm, which is a deal struck between yield and speed. Ammonia is pulled out as a liquid as it forms, which drags the balance forward.

Ammonia itself is a trigonal pyramid with H–N–H angles near 107°. It boils at −33 °C, so it is easy to store under mild pressure. In water it is a weak base:

NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH−(aq)    Kb = 1.8 × 10−5

The nitrogen oxides

Nitrogen forms an oxide at every oxidation state from +1 to +5. Dinitrogen oxide, N2O, is the dental gas. Nitrogen monoxide, NO, is a colourless gas with an odd number of electrons, which makes it a radical. Your own blood vessels use it as a signal. Nitrogen dioxide, NO2, is the brown haze over a busy city. It is also a radical, and it pairs up when cooled:

2 NO2(g) ⇌ N2O4(g)    ΔH = −57.2 kJ

Brown NO2 fades to colourless N2O4 in an ice bath. Warm the tube and the colour floods back. It is one of the clearest equilibrium demonstrations there is.

Nitric acid from ammonia

The Ostwald process turns ammonia into nitric acid in three steps. A platinum and rhodium gauze does the first one near 850 °C:

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) 2 NO(g) + O2(g) → 2 NO2(g) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g)

The NO from the last step is piped back and used again. Nitric acid is a strong acid, but it is also a strong oxidizer, and that second job matters more. Copper will not touch hydrochloric acid. It dissolves in nitric acid at once, because the nitrate ion does the work. The product depends on how concentrated the acid is:

Cu(s) + 4 HNO3(conc) → Cu(NO3)2(aq) + 2 NO2(g) + 2 H2O(l) 3 Cu(s) + 8 HNO3(dilute) → 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H2O(l)
From air to nitric acid: the Haber and Ostwald processes Air in, fertilizer and explosives out N₂ + 3 H₂78% of air + steam reformed H₂ Haber450 °C, 200 atm, Fe 2 NH₃ΔH = −92.2 kJ + 5 O₂Pt/Rh gauze, 850 °C 4 NOcolourless radical + O₂cool to 25 °C NO₂brown 2 HNO₃strong acid, strong oxidant 3 NO₂ + H₂O → 2 HNO₃ + NO the leftover NO is recycled NH₄NO₃ and fertilizerabout 80% of all output The triple bond in N₂ is worth 945 kJ/mol, so step one needs pressure, heat and a catalyst. Every later step is downhill.
Air to acid. The Haber step is the hard one, because it has to break the triple bond. Ostwald then walks nitrogen up through NO and NO2 to nitric acid. Most of the output ends as ammonium nitrate fertilizer.

Phosphorus comes in three solids

White phosphorus is built from P4 molecules shaped like a tiny tetrahedron. The bond angles are forced to 60°, far from the 109.5° the atom wants. That strain makes it wildly reactive. White phosphorus catches fire in air near 34 °C, so it is kept under water. Heat it gently and it turns into red phosphorus, a chain polymer safe enough for match strikers. Heat it under pressure and you get black phosphorus, a layered solid much like graphite.

Phosphorus burns in air to give one of two oxides. Starve it of oxygen and you get P4O6. Give it plenty and you get P4O10, a white powder so thirsty that chemists use it to dry other gases:

P4(s) + 3 O2(g) → P4O6(s) P4(s) + 5 O2(g) → P4O10(s) P4O10(s) + 6 H2O(l) → 4 H3PO4(aq)

The phosphorus acids

Phosphoric acid, H3PO4, gives up three protons, one at a time, each much harder than the last. Its three acid constants are 7.5 × 10−3, 6.2 × 10−8 and 4.2 × 10−13. The middle one sits close to blood pH, which is why phosphate is a body buffer. Most of it is made by pouring sulfuric acid on phosphate rock:

Ca3(PO4)2(s) + 3 H2SO4(aq) → 2 H3PO4(aq) + 3 CaSO4(s)

Now the trap. Phosphorous acid is written H3PO3, so it looks triprotic. It is not. One of its three hydrogens is bonded straight to phosphorus, and a P–H hydrogen never leaves in water. Only the two O–H hydrogens are acidic, so H3PO3 is diprotic. Hypophosphorous acid, H3PO2, has two P–H bonds and gives up just one proton. The rule to carry away is simple. Count the O–H groups.

Only a hydrogen bonded to oxygen can leave Count the O–H groups, not the hydrogens Phosphoric acid H₃PO₄ P O O–H O–H O–H triprotic pKₐ₁ = 2.12 Phosphorous acid H₃PO₃ P O O–H O–H H diprotic pKₐ₁ = 1.3 Hypophosphorous acid H₃PO₂ P O O–H H H monoprotic pKₐ₁ = 1.2
Count the O–H groups. Gold boxes mark hydrogens bonded to oxygen, which can leave. Grey boxes mark hydrogens bonded straight to phosphorus, which cannot. The formula alone would fool you all three times.

Worked example · pH of 0.10 M phosphoric acid

Find the pH of 0.10 M H3PO4. Use only Ka1 = 7.5 × 10−3, since the later steps give far less H+.

Step 1 · set upLet x = [H+] at equilibrium. Then x2 / (0.10 − x) = 7.5 × 10−3.

Step 2 · check the shortcutKa1 is only about 13 times smaller than 0.10. So you cannot drop the x in the bottom. Use the full quadratic.

Step 3 · solvex2 + 7.5 × 10−3x − 7.5 × 10−4 = 0. The quadratic formula gives x = (−0.0075 + 0.05528) / 2 = 0.0239 M.

Step 4 · take the logpH = −log(0.0239) = 1.62.

Step 5 · check itDrop the shortcut back in and you would get x = 0.0274 M and pH 1.56. The quadratic answer is the honest one. Either way the acid is strong enough to sting, which fits a soft drink ingredient used in small amounts.

Key points
  • The N2 triple bond at 945 kJ/mol is why nitrogen is so slow to react.
  • Haber makes ammonia at about 450 °C and 200 atm over iron. The conditions trade yield for speed.
  • Ostwald oxidizes ammonia to NO, then NO2, then nitric acid, and recycles the leftover NO.
  • Nitric acid attacks metals as an oxidizer. Concentrated acid gives NO2, dilute acid gives NO.
  • White P4 is strained and catches fire in air. Red and black phosphorus are tamer.
  • A hydrogen bonded to phosphorus is not acidic. H3PO4 is triprotic, H3PO3 diprotic, H3PO2 monoprotic.
Interactive Follow nitrogen and phosphorus through their oxides and acids. Open full ↑

Section 5Oxygen and sulfur

Oxygen has a second form

Oxygen gas is 21% of the air by volume. Its double bond is worth 498 kJ/mol, just over half of the nitrogen triple bond, which is why oxygen reacts so readily. O2 also has two unpaired electrons, so a pool of liquid oxygen clings to a magnet. Industry gets it by chilling air until it liquefies, then boiling the nitrogen off at −196 °C and the oxygen at −183 °C.

Oxygen also comes as ozone, O3, an allotrope with a bent shape and a 117° angle. Both O–O bonds are 128 pm, which sits between a single bond and a double bond. Neither bond is whole, because the real structure is an average of two drawings. Making ozone costs energy:

3 O2(g) → 2 O3(g)    ΔH = +285.4 kJ

High in the air, ultraviolet light pays that bill and ozone shields the ground. At ground level the same gas is a lung irritant. Position, not chemistry, decides whether ozone helps you.

Oxide, peroxide, superoxide

Oxygen is almost always −2, but not always. In a peroxide the ion is O22− and each oxygen is −1. In a superoxide the ion is O2− and each oxygen is −½. Adding electrons fills antibonding levels, so the bond order drops and the O–O distance grows.

Adding electrons to O2 weakens the oxygen oxygen bond Each electron you add stretches the O–O bond SPECIES BOND ORDER AND LENGTH O STATE O₂ dioxygen bond order 2.0 · 121 pm two unpaired electrons, so it is drawn to a magnet 0 O₂⁻ superoxide bond order 1.5 · 133 pm one spare electron, found in KO₂ −½ O₂²⁻ peroxide bond order 1.0 · 149 pm the O–O bond in H₂O₂ and Na₂O₂ −1 O²⁻ oxide single ion, no O–O bond no O–O bond left at all −2 Four electrons in, and the bond that started at 498 kJ/mol is gone.
One family, four rungs. Going down the list you add one electron at a time. Bond order falls from 2 to 1 to 0 and the bond stretches from 121 pm to 149 pm before it breaks for good.

These ions are useful. Sodium peroxide gives hydrogen peroxide with water. Potassium superoxide gives oxygen, which is why it fills emergency breathing canisters in mines and submarines:

Na2O2(s) + 2 H2O(l) → 2 NaOH(aq) + H2O2(aq) 4 KO2(s) + 2 CO2(g) → 2 K2CO3(s) + 3 O2(g)

Hydrogen peroxide is caught in the middle of its own range, so it can be oxidized or reduced. Left alone it does both at once and tears itself apart. A speck of manganese dioxide, or the enzyme in a cut finger, makes the split instant:

2 H2O2(aq) → 2 H2O(l) + O2(g)

Sulfur: rings that open

Sulfur sits under oxygen but behaves very differently. It is too big for strong double bonds, so instead of S2 it builds eight atom rings shaped like a crown. Solid S8 is rhombic below 95.3 °C and monoclinic above it, and it melts near 115 °C. Keep heating and the rings snap open into long chains. The liquid gets darker and thicker, which is odd for a hot liquid. Pour it into cold water and the tangle freezes as rubbery plastic sulfur.

Most sulfur now comes out of oil and gas as hydrogen sulfide. The Claus process turns that waste into solid sulfur:

2 H2S(g) + SO2(g) → 3 S(s) + 2 H2O(g)

Hydrogen sulfide is a weak diprotic acid with Ka1 near 1.0 × 10−7. It smells of rotten eggs at tiny amounts. At higher amounts it numbs the nerve that detects it, so the warning disappears while the danger grows.

The contact process

Sulfuric acid is made in larger amounts than any other chemical. The route is the contact process, and it has four steps. Burn sulfur, oxidize the dioxide over a catalyst, absorb the trioxide into strong acid, then add water:

S(s) + O2(g) → SO2(g) 2 SO2(g) + O2(g) ⇌ 2 SO3(g)    V2O5, 430 °C, ΔH = −198 kJ SO3(g) + H2SO4(l) → H2S2O7(l) H2S2O7(l) + H2O(l) → 2 H2SO4(l)

Only the second step is reversible, and it is the one that needs care. Cool gas favours SO3 but reacts too slowly, so the plant settles near 430 °C with a vanadium oxide catalyst. The third step looks like a detour. It is there because SO3 met with water throws a fine acid mist that no tower can trap. The oleum route keeps the product in the liquid.

The contact process for sulfuric acid Four steps to the world’s most used chemical S(s)mined or from sour gas burn in airS + O₂ → SO₂ SO₂(g)sharp smell V₂O₅, 430 °C2 SO₂ + O₂ ⇌ 2 SO₃ SO₃(g)ΔH = −198 kJ into 98% acidSO₃ + H₂SO₄ → H₂S₂O₇ oleumH₂S₂O₇ + H₂O 2 H₂SO₄98% is about 18 M Why the detour through oleum? SO₃ poured straight into water throws a fine acid mist that is very hard to collect. Oleum avoids it. Step two is the only reversible step. Low heat favours SO₃ but runs slowly, so the plant settles near 430 °C. Sulfuric acid then goes to fertilizer, batteries, metal pickling and dozens of other jobs.
The contact process. Sulfur in, sulfuric acid out. The reversible middle step sets the conditions, and the oleum step exists only to avoid acid mist.

Concentrated sulfuric acid is about 98% by mass, which works out near 18 M. It is a strong acid on the first proton and a weak one on the second, with Ka2 = 1.2 × 10−2. It is also a powerful drying agent. Pour it on table sugar and it strips out the water, leaving a black column of carbon. Sulfur dioxide gives the weaker sulfurous acid, which bleaches paper, preserves dried fruit and falls as acid rain:

SO2(g) + H2O(l) ⇌ H2SO3(aq)    Ka1 = 1.4 × 10−2

Worked example · acid from a ton of sulfur

A plant feeds 1.00 metric ton of sulfur into the contact process. If every step ran perfectly, how much sulfuric acid comes out?

Step 1 · follow the atomsEach step carries one sulfur atom forward. So 1 mol S gives 1 mol SO2, then 1 mol SO3, then 1 mol H2SO4.

Step 2 · moles of sulfur1.00 × 106 g ÷ 32.06 g/mol = 3.119 × 104 mol S.

Step 3 · mass of acid3.119 × 104 mol × 98.08 g/mol = 3.06 × 106 g = 3.06 metric tons.

Step 4 · sanity checkThe acid weighs about three times the sulfur. That fits, since 98.08 ÷ 32.06 = 3.06. The extra mass is the oxygen and water the sulfur picks up.

Worth knowing. Mixing concentrated sulfuric acid with water gives out a lot of heat. Always add the acid to the water in a slow stream, never water to the acid. Water poured on acid can boil on contact and spit the acid back out.
Key points
  • O2 has two unpaired electrons and a 498 kJ/mol double bond, so it reacts far more easily than N2.
  • Ozone is bent, costs energy to make, and shields the ground from above while irritating lungs at ground level.
  • Oxide, peroxide and superoxide run −2, −1 and −½. More electrons means a longer, weaker O–O bond.
  • Sulfur rings open on heating, which is why molten sulfur thickens instead of thinning.
  • The contact process is burn, catalyse, absorb into oleum, then dilute. Only the SO3 step is reversible.
  • Sulfuric acid is strong on the first proton, weak on the second, and a fierce drying agent besides.
Interactive Compare oxides, peroxides and the sulfur oxyacids. Open full ↑

Section 6Halogens and noble gases

The halogens are one electron short

The halogens are fluorine, chlorine, bromine, iodine and astatine. Each has seven outer electrons, written ns2np5. Each needs one more to fill the shell, so each is a hungry oxidizer. All five exist as X2 molecules, and the way they look changes right down the group. Fluorine is a pale yellow gas, chlorine a yellow green gas, bromine a red brown liquid and iodine a grey violet solid.

Their appetite for electrons is measured by the standard reduction potential. Fluorine leads at +2.87 V, then chlorine at +1.36 V, bromine at +1.07 V and iodine at +0.54 V. That order lets you predict every displacement reaction. Any halogen pushes a halide ion from lower in the list out of its compound:

Cl2(aq) + 2 Br−(aq) → 2 Cl−(aq) + Br2(aq)

Fluorine does not stop at halides. It takes electrons from water itself:

2 F2(g) + 2 H2O(l) → 4 HF(aq) + O2(g)

Chlorine is gentler. In water it splits its own oxidation states, a move called disproportionation. In base the same reaction runs further and gives household bleach:

Cl2(g) + H2O(l) ⇌ HOCl(aq) + HCl(aq) Cl2(g) + 2 NaOH(aq) → NaCl(aq) + NaOCl(aq) + H2O(l)
Halogen oxidizing power falls down the group but bond strength peaks at chlorine Two trends that do not match Oxidizing power falls in a straight line. Bond strength does not, and that is why fluorine is so savage. E° for X₂ + 2e⁻ → 2X⁻ (volts) F₂ +2.87 V pale yellow gas Cl₂ +1.36 V yellow green gas Br₂ +1.07 V red brown liquid I₂ +0.54 V grey violet solid X–X bond energy (kJ/mol) F₂ 159 Cl₂ 243 Br₂ 193 I₂ 151 F₂ is weakest. Three lone pairs on each tiny atom crowd together and push the bond apart. A halogen displaces any halide below it in this list.
Strength and weakness together. Oxidizing power drops steadily from fluorine to iodine. Bond energy peaks at chlorine instead. The weak F–F bond is easy to break, which adds to fluorine's bite.

That bond energy chart holds a surprise. The F–F bond is only 159 kJ/mol, weaker than the Cl–Cl bond at 242 kJ/mol. Fluorine atoms are so small that their lone pairs crowd each other and push the bond apart. A bond that cheap to break, plus a huge gain from forming F−, is why fluorine attacks almost everything.

Halogen acids and oxyacids

Three of the four hydrogen halides are strong acids. Hydrofluoric acid is the odd one out. Its Ka is 6.8 × 10−4, because the H–F bond is worth 569 kJ/mol and does not want to break. Weak does not mean safe. HF soaks through skin and attacks bone, and it is the only common acid that eats glass:

SiO2(s) + 4 HF(aq) → SiF4(g) + 2 H2O(l)

Chlorine also makes a set of oxyacids, and each extra oxygen makes the acid stronger. Hypochlorous acid is very weak, with Ka = 2.9 × 10−8. Chlorous acid is far stronger at 1.1 × 10−2. Chloric and perchloric acids are both strong, and perchloric is one of the strongest acids known. The reason is the leftover ion. Extra oxygens pull electron density away and spread the negative charge, so the ion holds together without the proton.

Interhalogens

Halogens also bond to each other. An interhalogen has the formula AB, AB3, AB5 or AB7. The larger, less electronegative halogen always sits in the middle, because only a big atom has room for several neighbours. Chlorine monofluoride, ClF, is linear. Bromine trifluoride, BrF3, is T shaped. Iodine pentafluoride, IF5, is a square pyramid. Only iodine is wide enough to hold seven fluorines, so IF7 is the one AB7 that exists.

These compounds are savage fluorinating agents. Chlorine trifluoride sets fire to glass wool, sand and concrete. It was tested as a rocket oxidizer and then quietly dropped.

Worked example · will bromine displace iodide?

Bromine water is poured on a potassium iodide solution. Does the reaction go, and how much free energy does it release?

Step 1 · write the halvesBr2 + 2 e− → 2 Br− has E° = +1.07 V. I2 + 2 e− → 2 I− has E° = +0.54 V.

Step 2 · build the cellBromine is the stronger oxidizer, so it takes the electrons and iodide gives them up. E°cell = 1.07 V − 0.54 V = +0.53 V. A positive value means it goes.

Step 3 · the equationBr2(aq) + 2 I−(aq) → 2 Br−(aq) + I2(aq). The solution turns brown as iodine appears.

Step 4 · free energyΔG° = −nFE° = −(2)(96,485 C/mol)(0.53 V) = −1.02 × 105 J = −102 kJ.

Step 5 · turn it aroundTry iodine on bromide and E°cell = 0.54 − 1.07 = −0.53 V. Negative, so nothing happens. The ranking only works one way.

The noble gases hold back

The noble gases are helium, neon, argon, krypton, xenon and radon. Each has a filled outer shell, so each has nothing to gain by bonding. That shows up in their ionization energies, which are the highest in every period. Helium needs 2372 kJ/mol. Argon needs 1521 kJ/mol. All six are gases that boil far below room temperature, and all are single atoms rather than pairs.

Still, the heavier ones do react. Xenon needs only 1170 kJ/mol to lose an electron, which is about the same as an oxygen molecule at 1175 kJ/mol. Since oxygen can be forced to give up an electron, xenon should be able to as well. That single comparison led to the first noble gas compound. Fluorine is the partner, and the amount you use sets the product:

Xe(g) + F2(g) → XeF2(s) Xe(g) + 2 F2(g) → XeF4(s) Xe(g) + 3 F2(g) → XeF6(s)

XeF2 is linear and XeF4 is square planar, both shaped by extra lone pairs on xenon. Water turns the fluorides into xenon trioxide, which is a violent explosive:

XeF6(s) + 3 H2O(l) → XeO3(aq) + 6 HF(aq)

Their everyday jobs come from not reacting. Helium lifts balloons and cools magnets. Argon fills the space around a weld so the hot metal cannot meet oxygen. Neon glows red orange in a tube, and krypton and xenon run bright lamps and camera flashes.

Group 17 factFClBrI
State at 25 °Cgasgasliquidsolid
E° for X2/X− (V)+2.87+1.36+1.07+0.54
X–X bond (kJ/mol)159242193151
H–X bond (kJ/mol)569431366298
HX in waterweakstrongstrongstrongest
Electronegativity3.983.162.962.66
Key points
  • Halogen oxidizing power falls from fluorine to iodine, and that order predicts every displacement.
  • The F–F bond is weaker than the Cl–Cl bond because lone pairs crowd on a tiny atom.
  • HF is a weak acid because the H–F bond is strong. It is still the acid that etches glass.
  • More oxygens make a halogen oxyacid stronger, so HClO4 beats HClO by a huge margin.
  • In an interhalogen the bigger halogen goes in the middle. Only iodine can hold seven fluorines.
  • Xenon reacts because its ionization energy nearly matches that of O2. Fluorine gives XeF2, XeF4 and XeF6.
Interactive Compare halogen reactivity and see why noble gases hold back. Open full ↑

The chapter in one breath

  • Two trends run everything. Across a period the nuclear grip tightens. Down a group a new shell loosens it.
  • Oxides mark the map. Basic on the left, amphoteric at the border, acidic on the right.
  • Groups 1 and 2 give electrons away. Every alkali metal makes hydrogen and a hydroxide in water, faster as you go down.
  • Boron is short of electrons and aluminum is armoured. One acts as a Lewis acid, the other hides behind its own oxide film.
  • Structure decides properties. Diamond, graphite, quartz and asbestos are all networks of the same few atoms.
  • Nitrogen is hard to start and easy to finish. Haber breaks the triple bond, then Ostwald walks nitrogen up to nitric acid.
  • Count O–H groups, not hydrogens. That is how H3PO3 ends up diprotic.
  • Oxygen stretches as it gains electrons. Oxide, peroxide and superoxide are the same pair of atoms with different loads.
  • Halogens rank by appetite. Fluorine first, iodine last, and the ranking predicts every displacement and the noble gas compounds too.

ReferenceWords worth knowing

These are the words this chapter leans on. Come back to them before a quiz.

alkali metal
A group 1 element. One outer s electron, a +1 ion, and a fast reaction with water.
alkaline earth metal
A group 2 element. Two outer s electrons and a +2 ion. Harder and slower to react than group 1.
allotrope
A different solid form of the same element. Diamond and graphite are allotropes of carbon.
amphoteric
Able to react as an acid and as a base. Al2O3 and BeO both qualify.
contact process
The four step industrial route to sulfuric acid: burn sulfur, oxidize SO2 over V2O5, absorb SO3 into acid, then add water.
cryolite
Na3AlF6. Molten cryolite dissolves alumina so aluminum can be won at about 960 °C instead of 2072 °C.
disproportionation
One substance is oxidized and reduced in the same reaction. Chlorine in water gives HOCl and HCl.
effective nuclear charge
Written Zeff. The share of the nuclear charge an outer electron actually feels after inner electrons screen it.
Haber process
Making ammonia from N2 and H2 over iron, near 450 °C and 200 atm.
halogen
A group 17 element. Seven outer electrons, an X2 molecule, and a strong pull for one more electron.
interhalogen
A compound of two different halogens, such as BrF3 or IF7. The larger halogen sits in the middle.
metallic character
How readily an element gives electrons up and behaves as a metal. It rises down a group and falls across a period.
metalloid
An element on the staircase border with some metal and some nonmetal behaviour. Boron, silicon, germanium, arsenic, antimony and tellurium.
nitrogen fixation
Turning unreactive N2 into usable compounds such as ammonia or nitrate.
noble gas
A group 18 element. A filled outer shell, a very high ionization energy, and single atoms rather than molecules.
oleum
H2S2O7, made by feeding SO3 into concentrated sulfuric acid. It avoids the acid mist that water would cause.
Ostwald process
Making nitric acid from ammonia in three steps, through NO and then NO2.
peroxide
A compound holding the O22− ion, with oxygen at −1 and a single O–O bond.
silicate
A mineral built from SiO4 tetrahedra sharing corners. Sharing none gives separate ions, sharing all four gives quartz.
superoxide
A compound holding the O2− ion, with oxygen at −½. KO2 is the common example.

Check yourself

1. Sodium oxide, aluminum oxide and sulfur trioxide are all period 3 oxides. Sort them as basic, amphoteric or acidic, and say what fixes the order.
Na2O basic, Al2O3 amphoteric, SO3 acidic. Metallic character falls from left to right, so the oxide bonding shifts from ionic to covalent. Aluminum sits on the border, so its oxide reacts with acid and with base.
2. Drop 4.00 g of calcium into excess water. What volume of hydrogen forms at 0 °C and 1.00 atm?
2.24 L. Ca + 2 H2O → Ca(OH)2 + H2. Moles of Ca = 4.00 g ÷ 40.08 g/mol = 0.0998 mol. The ratio is 1 to 1, so 0.0998 mol H2. Then V = nRT/P = (0.0998)(0.08206)(273.15) ÷ 1.00 = 2.24 L.
3. A smelter must deliver 1.00 kg of aluminum. How much charge does that take? Use F = 96,485 C/mol.
1.07 × 107 C. Moles of Al = 1000 g ÷ 26.98 g/mol = 37.06 mol. Al3+ needs 3 electrons, so 37.06 × 3 = 111.2 mol e−. Charge = 111.2 mol × 96,485 C/mol = 1.07 × 107 C.
4. Carbon dioxide is a gas at room temperature. Silicon dioxide is sand. Both are group 14 dioxides, so why the huge difference?
Carbon can form strong double bonds and silicon cannot. Carbon is small, so its p orbitals overlap sideways well. Two double bonds finish the CO2 molecule, and separate molecules drift apart as a gas. Silicon is larger and that sideways overlap is weak, so it makes four single bonds to oxygen and builds an endless network solid.
5. A kiln is fed 1.00 kg of pure calcium carbonate. What mass of quicklime comes out?
560 g. CaCO3 → CaO + CO2. Moles of CaCO3 = 1000 g ÷ 100.09 g/mol = 9.991 mol. The ratio is 1 to 1, so 9.991 mol CaO × 56.08 g/mol = 560 g. The missing 440 g left as carbon dioxide, and 560 + 440 = 1000 g checks out.
6. Phosphorous acid is written H3PO3. How many protons can it actually give up, and how do you know?
Two. It is diprotic. Only a hydrogen bonded to oxygen is acidic. H3PO3 has two O–H groups and one hydrogen bonded straight to phosphorus. The P–H hydrogen does not leave in water. By the same rule H3PO2 is monoprotic.
7. Find the pH of a 0.050 M solution of hydrofluoric acid. Ka = 6.8 × 10−4.
pH = 2.26. Set x2/(0.050 − x) = 6.8 × 10−4, so x2 + 6.8 × 10−4x − 3.4 × 10−5 = 0. The quadratic formula gives x = (−0.00068 + 0.011682) ÷ 2 = 0.00550 M. pH = −log(0.00550) = 2.26.
8. An ammonia plant must make 1.00 kg of NH3. What volume of nitrogen gas does that need at 0 °C and 1.00 atm?
658 L. N2 + 3 H2 → 2 NH3. Moles of NH3 = 1000 g ÷ 17.03 g/mol = 58.72 mol. Nitrogen needed = 58.72 ÷ 2 = 29.36 mol. Then V = (29.36)(0.08206)(273.15) ÷ 1.00 = 658 L.
9. Why does the contact process feed SO3 into concentrated sulfuric acid instead of straight into water?
To stop an acid mist forming. SO3 met with water gives off so much heat that the acid leaves as a fine fog, and a fog is almost impossible to collect. Absorbing it into 98% acid gives liquid oleum, H2S2O7, which is then diluted to twice the acid you started with.
10. Chlorine water is added to sodium bromide solution. Will anything happen? Work out E°cell and ΔG°. Use E° = +1.36 V for Cl2 and +1.07 V for Br2.
Yes. E°cell = +0.29 V and ΔG° = −56.0 kJ. Chlorine is the stronger oxidizer, so Cl2 + 2 Br− → 2 Cl− + Br2. E°cell = 1.36 − 1.07 = +0.29 V. Then ΔG° = −nFE° = −(2)(96,485)(0.29) = −5.60 × 104 J = −56.0 kJ. The solution turns orange as bromine forms.
11. Hydrochloric acid is strong but hydrofluoric acid is weak. Fluorine is the more electronegative element, so explain the result.
The H–F bond is too strong to break. Acid strength here depends on losing the proton, not on electronegativity. H–F is worth 569 kJ/mol while H–Cl is only 431 kJ/mol. Fluoride is also small, so it holds the proton tightly in water. Ka for HF is 6.8 × 10−4, which is weak but far from harmless.
12. Xenon forms XeF2, XeF4 and XeF6, but neon forms nothing. What makes xenon different?
Xenon holds its outer electrons far more loosely. Xenon's first ionization energy is 1170 kJ/mol, close to the 1175 kJ/mol of an O2 molecule, and oxygen can be forced to give an electron up. Neon needs 2081 kJ/mol, and no partner can pay that. Xenon is also large enough to fit several fluorine atoms around it.